Will it work?

Before the first experiment will be performed, the parts that have been acquired will need to be tested.  They are:

• 320Ω Resistor 
• 510 Ω Resistor
• Solderless Breadboard
• LED

The schematic:

 The real deal (without the battery - as an open circuit)

Will it work? Since V=IR, we can find the current by dividing the voltage (3V) over the total resistance, (510+320 = Ω) to find that the circuit will provide .0036A, or 3.6mA, well under the maximum current of the LED. 

And...

...everything works.  Couldn't say that about some other parts I've bought!